Question

iii.
A cell of e.m.f. 1.5 V and internal resistance 1 is connected to the
resistors of 4 and 202 in series. Draw a circuit diagram and calculate:
a. Current in the circuit,
b. p.d. across the cell, and
c. the voltage drop when the current is flowing​

Answer 1

.......................❤❤❤❤❤........

Answer 2

Explanation:

1+4+202 =207

Total Resistance=207

applied voltage = 1.5

according to ohms law I=v/r

current = 1.5/207 amps

b=c=1.5 volts