Question

(iii) AB and CB are two chords of circle. Prove that BO bisects angle B. [3]​

Answer 1

Answer:

ANSWER

(i) True, equal chords are equidistant from the centre .

(ii) True, In △

′

sOMB and ONB,

OM=ON(Proved in (i))

OB=BO(Common)

∠OMB=∠ONB=90

∘

therefore△OMB≅△ONB(RHS)

(iii)△OMB≅△ONB⇒∠OBM=∠OBN(cpct)

⇒BObisects∠ABC

Hence, all the statements are true statements