Question

iii) ABC একটি ত্রিভুজ। Sin(
B+C/2)​

Answer 1

$\huge {\underline{\pink{Given:-}}}$

Mass of boulder ,m = 600kg

Initial Velocity ,u = 68.6m/s

Final velocity ,v = 0m/s

Acceleration due to gravity ,a = 9.8m/s

$\huge {\underline{\red{To Find:-}}}$

Height of cliff ,h

$\huge {\underline{\green{Solution:-}}}$

Using third Equation of Motion

• v² = u² +2ah

Substitute the value we get

➺ 0² = 68.6² + 2× (-9.8) ×h

➺ 0 = 4705.96 + (-19.6) ×h

➺ -4705.96 = -19.6×h

➺ h = -4705.96/-19.6

➺ h = 4705.96/19.6

➺ h = 240.1m

Therefore, the height of the cliff is 240.1 metres.

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