Question

(iii) AC + AB > BC.​

Answer 1

Answer:

Theorem : The sum of two sides of a triangle is greater than the third side

Let PQR is a triangle.

Step-by-step explanation:

Proof:

Extend QP to A,

Such that, PA = PR

⇒ ∠ PAR = ∠ PRA

Since, By the diagram,

∠ ARQ > ∠ PRA

⇒ ∠ ARQ > ∠ PAR

⇒ QA > PQ ( Because, the sides opposite to larger angle is larger and the sides opposite to smaller angle is smaller )

⇒ QP + PA > QR

⇒ QP + PR > QR.

Hence, proved

Note: similarly we can proved, QP + QR > PR or PR + QR > QP

Thus, The sum of two sides of a triangle is greater than the third side

Note: Just rename the triangle as ABC