Question

iii) An electron with charge e enters a uniform magnetic field B with a velocity v.The Velocity is perpendicular to the magnetic field. The force on the charge e is given by|FI= Bev Obtain the dimensions of B.[Ans: [L'MºT']​

Answer 1

Answer:

Answer:

ThedimensionsofFluxDensity,BisM/T2I.

Explanation:

If charge moving at right angles to the field

F = -Bev for an electron ( e = charge on an electron)

Remember that the direction of conventional current is opposite to that of the electron.

Here, F is force measured in newtons (N)

B is flux density (the strength of a magnetic field I.e No. of magnetic lines of force from magnet per unit area) measured in teslas (T, named after Nikola Tesla)

So, The dimensions of Flux Density, B is MT^-2I^-1.

hope..it...helps...

Explanation:

Answer 2

Answer:

|F|=BeV

B=F/e

with dimensional analysis

Explanation: