Question

iii) An electron with charge e enters a uniform.
magnetic field B with a velocity v. The
velocity is perpendicular to the magnetic
field. The force on the charge e is given
by
F = Bev Obtain the dimensions of B.
[Ans: [L'MºT?I-']]
11
irodi writing answer proper
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Answer 1

Answer:

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Answer 2

Given : field B

Velocity = v

Charge= e

Solution:

F= Bve

For finding B = F/ve

First we will find dimension

Force = [L ^1 M^1 T^-2]

Velocity = [L^1 M^0 T^-1]

Charge = [L^0 M^0 T^1 I^1]

B = F/ve

      [L ^1 M^1 T^-2] ÷ [L^1 M^0 T^-1]             [L^0 M^0 T^1 I^1]

  = [L ^1 M^1 T^-2] × [L^-1 M^0 T^1]  ×             [L^0 M^0 T^-1 I^-1]

   = [L^0 M^1 T^-2 I^-1]

I hope it will help you