Math, asked by 003352, 20 days ago

iii) An elevator descends into a mine shaft at the rate of 5m/min. If the descent starts from 18m above the ground level, how long will it take to reach 182 m below the ground level?
please help me

Answers

Answered by sahiltambe03

1

Answer: 40 minutes

Step-by-step explanation:

Speed = 5m/min

Total distance= 18+182

=200m

Time= 200/5

= 40 minutes

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