Question

(iii) B played in all the four games. How would you find the mean​

Answer 1

answer is in attachment

Answer 2

Answer:

Step-by-step explanation

(i) Therefore, A's average number of points scored per game

\\ = \frac{14+16+10+10}{4} \\ = \frac{50}{4} \\ \\ = 12.5

(ii) Number of games C played = 3

Therefore, to find the mean, we will divide by 3

Mean of C =

\\ = \frac{8+11+13}{3} \\ = \frac{32}{3} \\ \\ = 10.67

(iii) Although he scored 0 in a match, he played all 4 games. Therefore, we will divide by 4.

Mean of B =  

\\ = \frac{0+8+6+4}{4} \\ = \frac{18}{4} \\ \\ = 4.5

(iv) Mean of A = 12.5

Mean of B = 4.5

Mean of C =  10.67

Since, A has the highest mean, A is t