Question

(iii) Calculate the volume of carbon dioxide at room temperature and pressure that can be
obtained from 30.0 g of glucose.

Answer 1

Answer:

2 C2H6 +7 O2=====> 4 CO2 + 6 H2O.

2 moles of ETHANE on combustion gives= 4 moles of CO2.

So 0.5 mole of ETHANE on combustion will produce= 4/2 x 0.5 =1 mole of CO2.

1 mole of CO2 at STP OCCUPIES= 22.4 LITRES.

At room temperature, ie., at 1-atm Pressure and 25°C, it will occupy= 22.4 x 298/273= 24.45 litres

Answer 2

Answer:

Explanation:

2 C2H6 +7 O2 => 4 CO2 + 6 H2O.

2 moles of Ethane on combustion gives: 4 moles of CO2.

So 0.5 mole of Ethane on combustion will produce= 4/2 x 0.5 =1 mole of CO2.

1 mole of CO2 at STP OCCUPIES= 22.4 LITRES.

At room temperature, ie., at 1-atm Pressure and 25°C, it will occupy= 22.4 x 298/273= 24.45 litres