Question

(iii) Can be worked out similarly.
We now consider some examples.
Example 3 Show that
(i) sin- (2xv1 – x2 ) = 2 sin-' x,
<x<
1
= 2 cos-1
X,
<x<1
(ii) sin-' (2xv1 – x?
Solution
(i) Let x = sin 8. Then sin-' x = 0. We have​

Answer 1

Answer:

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