Question

(iii) cot (x² sin 2x)​

Answer 1

Answer:

Given, cotx−2sin2x=1

⇒cotx−4cosxsinx=1

Substituting y=cotx, we get

y

2

+1

y(y

2

−3)

=1⇒y(y

2

−3)=y

2

+1

⇒y

3

−y

2

−3y−1=0⇒(y+1)(y

2

−2y−1)=0

⇒y=−1 or y=1±

2

⇒x=nπ−

4

π

,x=cot

−1

(1+

2

)+mπ,x=cot

−1

(1−

2

)+kπ

Answer 2

Answer:

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