Question

(iii) Factorise 16a2-b2 + 4b - 4.​

Answer 1

$\begin{gathered}\Large{\bold{\green{\underline{Formula \: Used \::}}}} \end{gathered}$

$(1)\rm \: \boxed{ \pink{ \bf \: {(x + y)}^{2} \: = \tt \: {x}^{2} + 2xy + {y}^{2} }}$

$(2)\rm \: \boxed{ \pink{ \bf \: {(x - y)}^{2} \: = \tt \: {x}^{2} - 2xy + {y}^{2} }}$

$(3)\rm \: \boxed{ \pink{ \bf \: {x}^{2} - {y}^{2} \: = \tt \:(x + y)(x - y) }}$

$\large\underline\purple{\bold{Solution :- }}$

$\rm :\implies\: {16a}^{2} - {b}^{2} + 4b - 4$

$\rm :\implies\: {16a}^{2} - ( { {b}^{2} - 4b + 4)}$

$\rm :\implies\: {16a}^{2} - ( {b}^{2} - 2 \times 2 \times b + {2}^{2} )$

$\rm :\implies\: {(4a)}^{2} - {(b - 2)}^{2}$

$\rm :\implies\:(4a + b - 2)(4a - b + 2)$

Answer 2

Answer:

Answer:(4a²v+ b-2)²(4a - b + 2)

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