Question

(iii) Find the 19th term of the A.P. 7. 13. 19. 25. ...​

Answer 1

Answer:

Answer

(first term ) = 7

d (common difference) = t2 -t1 = 13-7 = 6

n = 19

tn = a + ( n - 1 ) d

t19 = 7 + ( 19 - 1 ) 6

t19 = 7 + 108

$\sf \blue {19 = 115}$

Answer 2

To Find :-

• The 19ᵗʰ term of A.P.

Solution:

Given that,

• Sequence of A.P. = 7, 13, 19, 25 ...

∴ The common difference and the first term is :-

• First term = 7
• Common difference = 6

Since,

⇒ 13 - 7 = 6

⇒ 19 - 13 = 6

⇒ 25 - 19 = 6

According the question,

• The 19ᵗʰ term of A.P. is :-

We know,

• tₙ = a + ( n - 1 ) d,

Where,

• tₙ = nth term
• a = first term
• n = number of terms
• d = common difference.

Therefore,

⇒ tₙ = a + ( n - 1 ) d

⇒ t₁₉ = 7 + ( 19 - 1 ) 6

⇒ t₁₉ = 7 + ( 18 ) 6

⇒ t₁₉ = 7 + 18*6

⇒ t₁₉ = 7 + 108

⇒ t₁₉ = 115

Hence, The 19ᵗʰ term of A.P. is 115.

Required Answer:

• The 19ᵗʰ term of A.P. = 115.