(iii) Find the ratio in which the line segment joining the points A (3.8) and
B(-9, 3) is divided by the Y-axis,
Answers
Answered by
4
Let the dividing point , that is Y-axis be P(0,y)
Given A(3,8) B(-9,3)
Therefore let ,
x1= 3 , y1=8
x2=-9 , y2=3
Let the ratio be m1:m2.
Now applying section-formula for c-coordinate of P ,
0= (m1x2 + m2x1)/m1+m2
=> 0 = m1x2+ m2x1
0= m1(-9) + m2 (3)
=> 9m1=3m2
=> m1/m2 = 3/9 = 1/3
THEREFORE , m1:m2= 1:3
or ,
AB is divided by y-axis in the ratio , 1:3 .
Given A(3,8) B(-9,3)
Therefore let ,
x1= 3 , y1=8
x2=-9 , y2=3
Let the ratio be m1:m2.
Now applying section-formula for c-coordinate of P ,
0= (m1x2 + m2x1)/m1+m2
=> 0 = m1x2+ m2x1
0= m1(-9) + m2 (3)
=> 9m1=3m2
=> m1/m2 = 3/9 = 1/3
THEREFORE , m1:m2= 1:3
or ,
AB is divided by y-axis in the ratio , 1:3 .
Similar questions