Question

iii) Find the value of discriminant for V2 x2 + 4x + 2V2 = 0​

Answer 1

Answer:

Explanation:$v^{2} x^{2}+4x+2v^{2}=0$

The given quadratic eqn $v^{2} x^{2}+4x+2v^{2}=0$ with $ax^{2} +bx+c=0$

where a=$v^{2}$ , b=4,c=2$v^{2}$

D=$b^{2} -4ac$

= $4^{2}$-4.2$v^{2}$.$v^{2}$

=16-8v^4