Question

iii) For a SHM, if the maximum potential energy become double, choose the correct option.
a) Maximum KE will become double c) Total mechanical Energy will become double
b) Both (a) and (0)
d) Neither (a) nor (b)​

Answer 1

Answer:

right answer is (b) because mujhe lagata hai

Answer 2

Answer: The correct option is (d) Neither (a) nor (b)

Explanation:

In SHM, Potential energy (U) is given by

$U=\frac{1}{2}kx^{2}$

In SHM, Kinetic energy (T) is given by

$T=\frac{1}{2}mw^{2}(a^{2}-x^{2})$

Potential energy maximum is given by

U=$\frac{1}{2}ka^2$

If the potential energy is doubled then

$U^{'} = 2* \frac{1}{2} ka^{2}$ = $ka^{2}$ ,where a is the amplitude.

when potential energy increases, kinetic energy decreases.

Thus, at maximum potential energy kinetic energy is zero.

Total energy (E) is sum of kinetic energy and potential energy.

T.E = K.E+ P.E

T.E = $\frac{1}{2} mw^2(a^2-x^2) + \frac{1}{2}kx^2$

Thus, on doubling the potential energy the overall energy of the SHM will will remain the same.

Hence, option d is correct.