Question

III Given a = -3, b = 1 and c = 4, find the value of the following: 2. (-3b/9) *(4c²/7)


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Answer 1

Q. $\frac{-3b}{9}.\frac{4c^{2} }{7}$

Sol. i) Cancel terms that are in both the numerator and denominator:

$(\frac{-3b}{9}) (\frac{4c}{7})$

$(\frac{-b}{3})(\frac{4c}{7})$

ii) Combine multiplied terms into a single fraction:

$\frac{-b}{3}.\frac{4c^{2} }{7}$

$\frac{-b.4c^{2} }{3.7}$

iii) Multiply the numbers:

$\frac{-b}{3}.\frac{4c^{2} }{7}$

$\frac{-4bc^{2} }{3.7}$

iv) Multiply the numbers:

$\frac{-4bc^{2} }{21}$