Question

(iii) I am the square of the number that is 68 less than the product of the LCM of 2 and 3 and the LCM of 3 and 4. What number am I?​

Answer 1

Answer:

16

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Let the no. be x

$x = (LCM({2 \: 3}))(LCM({3 \: 4})) - 68 \\ x = (6 \times 12) - 68 \\ x = 72 - 68 \\ x = 4$

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