(iii) If
1-sin-A
cos²A
tan, then the value of 0 is ....
(A) 60°
(B) 45°
(C) 90°
(D) 30°
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Answer:
1-sin²A/cos²A=tanθ
cos²A/cos²A=tanθ
tanθ=1
θ=45°
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