Question

(iii) If p : 9 = 3 : 5 and q- p = 4 then (3p + 49) = ?​

Answer 1

Answer:

p:9=3:5

p/9=3/5

5p=27

p=27/5

q-p=4

q-27/4=4

q=4+27/4

q=43/4

3p+49

3×27/5+49

81/5+49

81+245/5

326/5

=65.2

Answer 2

Correct question:

If p:q = 3:5 and q-p = 4 then find (3p+4q)

__________________

Given:

• p:q = 3:5
• q-p = 4

To finD:

• (3p+4q)

Solution:

Given that p:q = 3:5. Let suppose that constant of ratio is x.

Therefore,

• p = 3x
• q = 5x

Now,

Given that q-p = 4 that means p is 3x and q is 5x.

So,

5x - 3x = 4

→ 2x = 4

→ x = $\large{\tt{\dfrac{4}{2}}}$

→ x = $\large{\tt{\cancel{\dfrac{4}{2}}}}$

→ $\large{\boxed{\mathbb{\green{x\:=\: 2}}}}$

Hence,

• p = 3x = 3×2 = 6
• q = 5x = 5×2 = 10

Now, we have to find (3p + 4q) in which we found that value of p and q is 6 and 10 respectively.

Finding (3p + 4q):

(3p + 4q)

→ [( 3×6)+(4×10)]

→ ( 18 + 40)

→ 58

Therefore,

$\large{\boxed{\red{\mathfrak{(3p+4q)\:=\: 58}}}}$