Question

(iii) If the height of a cone is doubled, then its volume is increased by
Surface area =
%​

Answer 1

Answer:

100 %

Step-by-step explanation:

Let the radius of the cone is r and volume is h then

volume of the cone = $\frac{1}3\\}$πr$r^{2}$h

if the height of the cone is double then,

New volume= $\frac{1}3\\}$πr$r^{2}$(2h) =  $\frac{2}3\\}$πr$r^{2}$h

increment of the volume= $\frac{2}3\\}$πr$r^{2}$h-  $\frac{1}3\\}$πr$r^{2}$h =  $\frac{1}3\\}$πr$r^{2}$h

%increase =  $\frac{1}3\\}$πr$r^{2}$h / $\frac{1}3\\}$πr$r^{2}$h × 100 = 100%

hope it helps