(iii) If total fare is '93, then find the total distance.
a. 16 km
b. 17 km
C. 18 km
d. 19
(ivt if the distance covered is 11 km, then find total fare.
a. `58
b. .68
c. '48R
(v) If fare for first kilometer isk)12 and fare has subsequent distance is
write a linear equation for this information.
a. 4x + y + 4 = 0 b. 6x+y+6=0 2.8x-y+4 = 0
d.
You
>
Answers
Answer:
ninety three km for physical therapy and support
Solution :-
Let the distance covered as x km and the total fare as ₹ y .
given that,
→ Fare for first km = Rs. 8
→ Fare for the subsequent distance = Rs. 5
So,
→ y = 1 * 8 + (x - 1) * 5
→ y = 8 + 5x - 5
→ y = 5x + 3
→ 5x - y + 3 = 0 (C)
comparing with ax + by + c = 0 we get,
→ a = 5 , b = (-1) , c = 3
So,
→ a + b + c = 5 - 1 + 3 = 7 (b)
now,
→ Total fare = Rs. 93
So,
→ y = 5x + 3
→ 93 = 5x + 3
→ 93 - 3 = 5x
→ 90 = 5x
→ x = 18 km (C)
now,
→ Distance = 11 km
So,
→ y = 5x + 3
→ y = 5 * 11 + 3
→ y = Rs. 58 (a)
now,
→ Fare for first km = Rs. 12
→ Fare for the subsequent distance = Rs. 8
So,
→ y = 1 * 12 + (x - 1) * 8
→ y = 12 + 8x - 8
→ y = 8x + 4
→ 8x - y + 4 = 0 (C)
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