Question

iii) IfAP and AQ are the two tangents a circle with centre O so that
anglePOQ = 110°, then anglePAQ is equal to
​

Answer 1

Answer:

70

Step-by-step explanation:

p +o+q+a=360

90+ 110 + 90+ a=360

360- 290= a

a= 70

Answer 2

Hey dost here is your answer.................

In quadrilateral APOQ,

<A + <Q +<P +<O = 360

<A + 90 + 90 + 110 = 360 (line from the center is perpendicular to the point of contact)

<A = 360 - 290

<A = 70

HOPE IT HELP YOU ....................