Physics, asked by swapnilmane2518, 1 month ago

iii. In a certain unit the radius of gyration of a uniform disc about its central and transverse axis is K. Its radius of gyration about a tangent in its plane (in the same unit) must be a. √5 2 b. √2 5 c. √2 d. ​

Answers

Answered by XxMissWorstxX
0

the moment of inertia ,I, by the parallel axis theorem is

I= I[c] +Ml^2 , here

I[c] =[1/4] M.r^2 , and since l=r Ml^2 = M.r^2 then.

I= [1/4]M.r^2 + Mr^2 = [5/4]M.r^2 is the moment of inertia perpendicular to the plane of the disc and tangent to the edge.

I= M k^2 where k is the radius of gyration

Mk^2= [5/4]M .r^2

k^2 =[5/4].r^2

k =[ sq rt 5].r/2

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