(iii) In the adjoining figure, seg QR is a tangent to the circle with centre O. Point Q is the point of contact. Radius of the circle is 10 cm. OR = 20 cm. Find the area of the shaded region. ( = 3.14, 3 = 1.73 )
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now subtract
area of shaded region = area of triangle - area of sector
= 173 -52.33
= 120.67 sq.cm
area of shaded region = area of triangle - area of sector
= 173 -52.33
= 120.67 sq.cm
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![](https://hi-static.z-dn.net/files/dee/ec1ed583b2b48ee7098659ae8b1c7549.jpg)
![](https://hi-static.z-dn.net/files/df6/5a1f434e54d606f99e344a37c6ab8ccd.jpg)
![](https://hi-static.z-dn.net/files/d08/1a20764739028827c61a718320063cd1.jpg)
![](https://hi-static.z-dn.net/files/d52/f565edbaaf54a2e3cd23c316884d61ad.jpg)
![](https://hi-static.z-dn.net/files/d68/2b1634ae12d108f6b718099c8c92a3a5.jpg)
cat1234:
thanks
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