(iii) In the adjoining figure, seg QR is a tangent to the circle with centre O. Point Q is the point of contact. Radius of the circle is 10 cm. OR = 20 cm. Find the area of the shaded region. ( = 3.14, 3 = 1.73 )
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now subtract
area of shaded region = area of triangle - area of sector
= 173 -52.33
= 120.67 sq.cm
area of shaded region = area of triangle - area of sector
= 173 -52.33
= 120.67 sq.cm
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thanks
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