Question

(iii) In the figure,
m(are NS) = 130",
m(arc EF) = 60°
then find
(a) angle NMS
(b) angle ENF.
(c) angle NFS​

Answer 1

Answer:

m(arc NS)=130°

m(arc EF)=60°

/_NMS has it vertex in the exterior of the circle and intercepts EF and arc NS.

/_NMS =1/2 [m(arc NS)-m(arc EF)]

/_NMS =1/2×[130-60]

/_NMS =1/2×70

/_NMS=35°

❤ HOPE IT HELPS U ❤

❤MARK AS A BRAINLIEST ❤