(iii) Marbles of diameter 1.4 cm are dropped into a beaker containing some water and
are fully submerged. The diameter of the beaker is 7 cm. Find how many marbles
have been dropped in it if the water rises by 5.6 cm.
Answers
Answered by
10
Answer:
n = 150
Step-by-step explanation:
Hi ,
Diameter of the Spherical ball ( d ) = 1.4cm
radius of the ball ( r ) = d/2
r = 0.7 cm
Volume of the Sphere = ( 4/3 )πr³ cm³
v = ( 4/3 ) π ( 0.7 )³ ----( 1 )
ii ) Diameter of the cylinder ( D ) = 7cm
radius of the cylinder ( R ) = D/2
R = 7/2 cm
Suppose water level rises by h= 5.6 cm
in the cylindrical beacker .
Then ,
Volume of the cylinder of height
h = 5.6 cm and radius 7/2 cm
V = πR²h
V = [ π ×( 7/2 )² × 5.6 ]cm³ ----( 2 )
Let the number of balls dropped in the
beaker = n
n = V /v
n = [π ×(7/2)²×5.6cm³]/ [4/3×π×(0.7)³cm³]
after cancellation ,we get
n = 150
I hope this helps you.
: )
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