Math, asked by bharatgupta12325knp, 3 months ago

(iii) n(B – A) = n(A U B) – n(A) = n(B) - n(An B)
(iv) n(A U B) = n(A - B) + n(B - A) + n(An B)
If & (universal set) is finite set and A is any set, then n(A) + n(A') =
These results are very useful in solving problems.
Example 6. If n(A) = 16, n(B) = 13 and n(A U B) = 22, then find n(A n B).
Solution. We know that
n(A U B) = n(A) + n(B) – n(A n B)
22 = 16 + 13 – n(A n B)
n(A n B) = 16 + 13 – 22
n(An B) = 7.
Example 7. If n(E) = 30, n(A') = 14, n(B) = 20 and n(An B) = 11, then find
(i) n(B')
(ii) n(A U B)
Solution. (i) We know that n(B') = n(E) – n(B)
n(B) = 30 - 20 = 10.
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Answers

Answered by Annu8M009
0

Answer:

(iii) n(B – A) = n(A U B) – n(A) = n(B) - n(An B)

(iv) n(A U B) = n(A - B) + n(B - A) + n(An B)

If & (universal set) is finite set and A is any set, then n(A) + n(A') =

These results are very useful in solving problems.

Example 6. If n(A) = 16, n(B) = 13 and n(A U B) = 22, then find n(A n B).

Solution. We know that

n(A U B) = n(A) + n(B) – n(A n B)

22 = 16 + 13 – n(A n B)

n(A n B) = 16 + 13 – 22

n(An B) = 7.

Example 7. If n(E) = 30, n(A') = 14, n(B) = 20 and n(An B) = 11, then find

(i) n(B')

(ii) n(A U B)

Solution. (i) We know that n(B') = n(E) – n(B)

n(B) = 30 - 20 = 10.

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Step-by-step explanation:

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