Math, asked by sayandeep30, 7 months ago

(iii) (p^2 - q^2r)^2+ 2p^2q^2r​

Answers

Answered by munmunroysarkar
2

Answer:

p⁴+q^4r²

Step-by-step explanation:

(p²- q^2r)²+ 2p²q^2r

= p⁴+q^4r²-2p²q^2r + 2p²q^2r

= p⁴+q^4r²

Answered by Arinjay6127
0

Answer:

(iii) (p^2 - q^2r)^2+ 2p^2q^2r

Step-by-step explanation:

(iii) (p^2 - q^2r)^2+ 2p^2q^2r

(iii) (p^2 - q^2r)^2+ 2p^2q^2r

(iii) (p^2 - q^2r)^2+ 2p^2q^2r

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