Question

(iii) (p - q)(p + 9) + (q – r)(q + r) + (r - p)(r + p) = 0 what is the answer of this question​

Answer 1

Answer:

Step-by-step explanation:

Given that,

( p - q ) ( p + q ) + ( q - r ) ( q + r ) + ( r - p ) ( r + p )=0 [∵(a +b) (a -b ) = a square - b square )

p square - q square + q square - r square + r square - p square = 0

p square - p square + q square - q square + r square - r square = 0

0 + 0 + 0 = 0

0 = 0 is the answer.