Question

(iii)
P
А
to
z
Z
B
yo
120°
115
с
Q
R
D​

Answer 1

In the figure we have :-

AB || CD

line PQ intersecting AB at PQ

A/q

=> < Q+ < P = 180° {consecutive interior angles}

=> 120° + <p = 180°

=> < P = 60 °

similarly

<R+<P = 180° { consecutive interior }

=> <P = 65°

Now ,

Here AB is a line and P is a point on it

,so

< X+< Y + < Z = 180° { straight angle prperty }

65° + <Y + 60 = 180°

<Y = 55°