Question

(iii) p(x)=x^2-1, x=1,-1​

Answer 1

Answer:

Step-by-step explanation:

p(x) = x^2-1

X = 1,-1

let first take x = 1

p(1) = 1^2-1

p(1) = 0

let next take x = -1

p(-1) = (-1)^2-1

p(-1) = 0

therefore, p(1) = p(-1)

Answer 2

$put \: the \: values \: of \: x \\x = 1 \\ \\ {x}^{2} - 1 \\ {1}^{2} - 1 \\ 1 - 1 \\ 0 \\ \\ x = - 1 \\ \\ {x}^{2} - 1 \\ { - 1}^{2} - 1 \\ 1 - 1 \\ 0$

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