Question

(iii) p(x) = X2 - x -12
Draw the graphs of the given polynomial and find the zeroes. Justify there
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Answer 1

Answer:

(- 3, 0), (4, 0)

Step-by-step explanation:

Graph of y = ax² + bx + c is parabola.

x-coordinate of vertex of parabola is $\frac{-b}{2a}$ and line $x=\frac{-b}{2a}$ is axis of symmetry of parabola.

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y = x² - x - 12

Coordinates of vertex are

$x=-\frac{-1}{2}$ = 1/2

$(\frac{1}{2})^{2} - \frac{1}{2} - 12 =$ - 12.25

1). Plot the vertex on coordinate plane;

2). Draw the line x = 1/2

3). Draw the parabola y = x² considering that axis of symmetry of parabola is shifted.

4). x-intercepts of parabola (- 3, 0) and (4, 0) are the zeroes of p(x).