Math, asked by sagarbasu2006, 5 hours ago


(iii) sin2 34° + sin2 56° + 2 tan 18° tan 72° - cot2 30°​

Answers

Answered by Maybellinee
1

Question:-

Sin2 24˚ + sin2 56˚ + 2 tan 18˚ tan 72˚ – cot2 30˚

Solution:-

 \tt = sin {}^{2} 34˚ + cos2 (90˚ – 56˚) + 2 tan 18˚ cot(90˚ – 72˚) – (√3) {}^{2}

 \tt = (sin {}^{2}  34˚ + cos {}^{2}  34˚) + 2 tan 18˚ ×  \frac{ 1}{tan 18˚ – 3}

= 1 + 2 – 3

= 3 – 3

= 0

\large \bold{@Maybellinee}

Answered by sunitapardeshi137
0

Answer:

are Bhai aap chup baitho

Similar questions