Chemistry, asked by nidhi17th, 1 month ago


(iii) Solutions A,B,C and D have pH values 3 ,4 ,5 and 6 respectively. Arrange them is increasing
order of acidic character​

Answers

Answered by amankumaraman11
1

pH of solution A – 3

pH of solution B – 4

pH of solution C – 5

pH of solution D – 6

Increasing order of acidic character of above solutions is as below :

 \huge \cal{D<C<B<A}

Answered by HA9650
2

HEY MATE....HERE'S YOUR ANSWER...!!

We know that, the acidic nature of a substance increase as the pH value decrease.

At the pH value of 7 the substance is said to be neutral and a substance with pH value of less than 7 is said to be acidic in nature.

So, according to the above data we can say that a substance with lowest pH value is more acidic than a substance of pH value less than 7 but around 7.

Therefore, the answer to your queation will be;

Solution A:- pH value=3

Solution A:- pH value=3Solution B:- pH value=4

Solution A:- pH value=3Solution B:- pH value=4Solution C:- pH value=5

Solution A:- pH value=3Solution B:- pH value=4Solution C:- pH value=5Solution D:- pH value=6

So, in the descending order of their acidic nature it will be;

Solution A >Solution B >Solution C >Solution D

And in ascending order it will be;

Solution D <Solution C <Solution B <Solution A

HOPE IT HELPS...HAVE A NICE DAY...!!

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