Question

iii) Solve: 14=3y+x; 20=2y -3x solve karke dikhao​

Answer 1

Answer:

2x−3y=13…(1)

2x−3y=13…(1)7x−2y=20…(2)

2x−3y=13…(1)7x−2y=20…(2)Let us use the elimination method for the given system of equations.

2x−3y=13…(1)7x−2y=20…(2)Let us use the elimination method for the given system of equations.Multiply (1) by 2 and (2) by −3. And add both the equations.

2x−3y=13…(1)7x−2y=20…(2)Let us use the elimination method for the given system of equations.Multiply (1) by 2 and (2) by −3. And add both the equations.4x−21x−+6y6y==26−60−17x=−34x=2

2x−3y=13…(1)7x−2y=20…(2)Let us use the elimination method for the given system of equations.Multiply (1) by 2 and (2) by −3. And add both the equations.4x−21x−+6y6y==26−60−17x=−34x=2Substitute the value of x in equation (1),

2x−3y=13…(1)7x−2y=20…(2)Let us use the elimination method for the given system of equations.Multiply (1) by 2 and (2) by −3. And add both the equations.4x−21x−+6y6y==26−60−17x=−34x=2Substitute the value of x in equation (1),2(2)−3y4−3y−3yy=13=13=9=−3

Hence, the value of x is equal to 2 and that of y is equal to −3.

Step-by-step explanation:

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