Question

(iii) tan 35° + tan 10° + tan 35°tan 10° = 1




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Answer 1

Answer:

sorry i dont know the answer

Step-by-step explanation:

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Answer 2

We use the identity

$tan (a-b)=\frac{tan \ a - tan\ b}{1+tan\ a \ tan\ b}$

And the fact  45 = 35 − 10 . and  tan 45 = 1 . Then

$tan\ 35=tan(45-10)=\frac{tan\ 45-tan\ 10}{1+tan\ 45 \ tan\ 10}$

Transposing terms, we have

$tan\ 35(1 + \ tan \ 10)=1-\ tan \ 10$$tan 35 + tan 35 \ tan 10 \ + \ tan 10=1QED$