Question

(iii) The coach of a cricket team buys 7 bats and 6 balls for 3800. Later, she buys 3
bats and 5 balls for 1750. Find the cost of each bat and each ball.​

Answer 1

Answer:

500

Step-by-step explanation:

let's bat is x and ball is y.

so,

7x+6y=3800 eq.1

3x+5y=1750 eq.2

by substitute method.

x=3800-6y/7 eq.3

putting x=3800-6y/7 into eq.2

then,3(3800-6y/7)+5y=1750

11400-18y+35y=12250

17y=850

y=850/17

y=50

putting y =50 in eq.1

then,7x+6×50=3800

7x+300=3800

7x=3800-300

7x=3500

x=3500/7

x=500

hope it helps,mark as brainliest

Answer 2

Answer:

Cost of each bat is 500

Cost of each ball is 50

Step-by-step explanation:

Let cost of each bat = Rs x

Cost of each ball = Rs y

Given that coach of a cricket team buys 7 bats and 6 balls for Rs 3800.

So that 7x + 6y = 3800

6y = 3800 – 7x

Divide by 6 we get

y = (3800 – 7x) /6 … (1)

Given that she buys 3 bats and 5 balls for Rs 1750.so that

3x + 5y = 1750

Plug the value of y

3x + 5 ((3800 – 7x) /6) = 1750

Multiply by 6 we get

18 x + 19000 – 35 x = 10500

-17x =10500 - 19000

-17x = -8500

x = - 8500 / - 17

x = 500

Plug this value in equation first we get

y = ( 3800 – 7 * 500) / 6

y = 300/6

y = 50

Hence cost of each bat = Rs 500 and cost of each balls is Rs 50