Question

(iii) The difference of two positive numbers is 48 and the quotient obtained on dividing the one by other is 4. The number are ?
(a) 9,63
(b) 16,64
(c) 20,74
(d) 16,70​

Answer 1

Answer:

16,64

Step-by-step explanation:

Answer 2

$\bf \underline{ \underline{\maltese\:Given} }$

$\sf The \: difference \: of \: two\: positive \: numbers \: is \: 48.$

$\sf The \: quotient \: obtained \: on \: dividing \: the \: one \: by \: other \: is \: 4.$

$\bf \underline{ \underline{\maltese\:To \: find} }$

$\sf \implies The \: numbers = \: ?$

$\bf \underline{ \underline{\maltese\:Solution} }$

$\sf Let \: us \: assume \: that,$

$\sf \implies First \: number \: be \: x$

$\sf \implies Second \: number \: y = (x - 48)$

$\bf \underline{Now},$

$\sf According \: to \: question,$

$\sf \implies Equation = \red{\bf \dfrac{x}{(x - 48)} = 4}$

$\sf \implies { \dfrac{x}{(x - 48)} = \dfrac{4}{1} }$

$\sf By \: doing \: cross \: multiplication,$

$\sf \implies 1(x) = 4(x - 48)$

$\sf \implies x = 4(x - 48)$

$\sf \implies x = 4x - 192$

$\sf \implies x - 4x = - 192$

$\sf \implies - 3x = - 192$

$\sf \implies x = \cancel \dfrac{- 192}{ - 3}$

$\sf \implies x = 64$

$\sf \: Thus, \: value \: of \: x \: (First \: number) = \bf 64$

$\bf \underline{Now},$

$\sf \implies Value \: of \: y = (x-48)$

$\sf \: Put \: value \: of \: x,$

$\sf \implies Value \: of \: y = \bf (64-48) = 64 - 48 = 16$

$\sf \bigstar \: \underline{ Hence, \: x = 64 \: and \: y = 16 }$

$\bf \underline{Therefore},$

$\sf \implies Both \: the \: numbers \: are \: \sf \bf 16, 64$