Question

iii) The magnitude of scalar product of two
unit vectors perpendicular to each other is
(A) zero (B) 1
(D) 2
(C)-1​

Answer 1

Answer:

A ) Zer0

Explanation:

i.j = (1)(1)cos90°          as          cos90° = 0

i.j = 0        

Answer 2

Answer:

The magnitude is found to be zero.

Explanation:

Let the two vectors be A and B.

The magnitude of scalar products of two unit vectors is determined by finding the dot product.

A.B = ABcosθ

So, A.B = AB cos 90 ( as the two vectors are perpendicular to each other so the angle between them is 90°).

As we know the value of cos90 is 0 so it becomes AB *0 = 0.

So the magnitude between the two vectors is zero.