Question

(iii) The sum of the digits of a two-digit number is 9. Also, nine times this number is
twice the number obtained by reversing the order of the digits. Find the number.
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Answer 1

Answer:

18

Step-by-step explanation:

Let The Two Digit Number Be 10x + y

A.T.Q;

x+y = 9

And 9[(10x +y)] = 2[(10y + x)]

y = 9-x

So,

9[10x +9-x] = 2 [ 10(9-x) +x]

9(9x-9) = 2(90-9x)

81x -81 = 180 - 18x

By Solving The Equation;

99x = 99

x = 1

From x+y = 9

1+y = 9

y = 8