Question

(iii) The sum of the digits of a two-digit number is 9. Also, nine times this number is
twice the number obtained by reversing the order of the digits. find the number​

Answer 1

Answer:

So, answer is 18

Step-by-step explanation:

To find number

Solution= let the unit digit and 10 digits of the number be X and Y

number = 10y+X

Number after reversing the digits = 10×+y

According to the question

=> x+y=9. (i)

=> 9(10y+x)=2(10×y)

=> 88y-11×=0 ...(ii)

Adding equation (i) and (ii)

=> 9y=9

=> y=1 ... (iii)

Putting the value in equation (i), we get

=> x=8

Hence, the number is 10y +x=10×1+8=18

Hope it helps u