Question

iii. The sum of two quantities is 4a² - 3ab + b². If one of them is
7a² +2ab-b², find the other.​

Answer 1

Answer:

Let the other number be x

Now,

x + 7a²+2ab-b² = 4a²-3ab+b²

x = 4a²-3ab+b² -(7a²+2ab-b²)

x = 4a²-3ab+b²-7a²-2ab+b²

x=-3a²-5ab+2b²

Hence,

The other number is -3a²-5ab+2b²