Math, asked by HarshdeepBedse, 11 months ago

(iii) Two taps A and B can together fill a
swimming pool in 15 days. Taps A and B are
kept open for 12 days and then tap B is
closed. It takes another 8 days for the pool to
be filled. How many days does each tap
require to fill the pool?​

Answers

Answered by sumit84271
6

Answer:

See A + B do work in 15 days right

A + B works together for 12 days means 15–12 = 3 days or 3 unit works remaining..

which A has to done all alone…which he do in 8 days right

We can easily find efficency of A = 3/8

efficiency of b = 1–3/8 = 5/8

now , A do whole work in total work/efficiency

ie 15/3/8 = 40 days

B do whole work in 15/5/8 = 24 days

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