Question

(iii) With solving , find the values of 'p' for which the equation x^2+(p-3)x+p=0 has real and equal roots.​

Answer 1

EXPLANATION.

→ Equation → x² + ( p - 3 )x + p = 0 has real

and equal roots.

→ To find the value of p.

→ conditions of real and equal roots.

→ D = 0 and b² - 4ac = 0

→ ( p - 3 )² - 4 ( 1) (p) = 0

→ p² + 9 - 6p - 4p = 0

→ p² - 10p + 9 = 0

→ p² - 9p - p + 9 = 0

→ p ( p - 9 ) -1 ( p - 9 ) = 0

→ ( p - 1 ) ( p - 9 ) = 0

→ p = 1 and p = 9

→ More information.

→ D > 0 and b² - 4ac > 0.

Roots are real and unequal.

→ D = 0 and b² - 4ac = 0.

Roots are real and equal.

→ D < 0 and b² - 4ac < 0.

Roots are imaginary.

Answer 2

Answer:

Step-by-step explanation:

 solving the following quadratic equation find the value of p for which the given equation has real and equal roots x2 p 3 x p 0