Question

(iii) Write down the essential condition for maximum height and maximum range for
projectile​

Answer 1

Answer:

The textbooks say that the maximum range for projectile motion (with no air resistance) is 45 degrees .if α = 45°, then the equation may be written as: hmax = h + V₀² / (4 * g) and in that case, the range is maximal if launching from the ground (h = 0). if α = 0°, then vertical velocity is equal to 0 (Vy = 0), and that's the case of horizontal projectile motion.

Answer 2

Hey there this is your answer...!!!!!

The textbooks say that the maximum range for projectile motion (with no air resistance) is 45 degrees.

hope this helps...!!!