Question

(iii) (x - 1) is a factor of x3 – 3x + 2. Hence,
fully factorise the polynomial.
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Answer 1

${x}^{3} - 3x + 2 \\ {x}^{3} - {x}^{2} + {x}^{2} - x - 2x + 2 \\ {x}^{2} (x - 1) + x(x - 1) - 2(x - 1) \\ (x - 1)( {x}^{2} + x - 2) \\ (x - 1)( {x}^{2} + 2x - x - 2) \\ (x - 1)(x(x + 2) - 1(x + 2)) \\ (x - 1)(x - 1)(x + 2)$

Answer 2

Answer:

(x-1)

x=1

p(1)=x³-3x+2

=(1)³-3(1)+2

=1-3+2

=0