Question

(iii) (x + 2) (x + 3) + (x-3) (x-2)-2x(x + 1) = 0
​

Answer 1

Answer:

Given that,

 (x+2)(x+3)+(x−3)(x−2)−2x(x+1)=0

⇒x  

2

+2x+3x+6+x  

2

−3x−2x+6−2x  

2

−2x=0

⇒2x  

2

−2x  

2

+5x−5x−2x+12=0

⇒−2x+12=0

⇒−2x=−12

⇒x=6

Answer 2

Answer:

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