(iii) (x + y,0) = (2,x-y)
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(1) from (2), we have
2x−y−(x−y)=2−0
2x−y−x+y=2
x=2
Substituting the value of x in eq
n
(1), we have
2−y=0
⇒y=2
Hence, x=2 and y=2.
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