Question

iii) x+z = 1, y+z = 1, x+y = 4​

Answer 1

Answer:

let 1st equation be x+z=1

let 2ñd be y+z=1

let 3rd be x+y=4

adding all three equation,we get

x+y+z=3 (4)

now,x=3-(y+z)

putting this value in eq.4

we get

y=2

now putting this value in eq 3

x=2

now putting this value in eq.in 4

z=-1

Answer 2

Answer:

z = -1 , y = 2 , x = 2

Step-by-step explanation:

By solving 1st and 2nd equation we get,

x + y + 2z = 2 , but we know x + y =4 , so

4 + 2z = 2, so 2z = -2 , so z = -2 /2 = -1

By substituting the value of z in equation no.2 we can get y-1 = 1 , so y = 1+1 = 2

By substituting value of y in equation no.3 we ca get x +2 =4 , so x = 4-2 =2

Therefore by solving the three equations we get , , , ,

x = 2 , , , ,

y = 2 , , , ,

z = -1 , , ,. . . .